What is the oxidation number of fe in fe(NO3)2
1. What is the oxidation number of fe in fe(NO3)2
Answer:
The oxidation number of Fe in is +2.
Explanation:
https://brainly.in/question/10588857#:~:text=The%20oxidation%20number%20of%20Fe%20in%20is%20%2B2.
2. What is the oxidation state of Al(NO3)3
Answer:
+5
Explanation:
Al(NO3)3 Al=3 o= -3
3+(3n+ -2*3*3)
3+(3n-18)
-15+3n =0
3n=+15
n=+5
3. element oxidized and reduced in Mg + 2NaNO3 ---- Mg (NO3)2 + 2Na
Answer:
2 Mg(NO3)2 → 2 MgO + 4 NO2 + O2This is an oxidation-reduction (redox) reaction:
4 NV + 4 e- → 4 NIV
(reduction)
2 O-II - 4 e- → 2 O0
(oxidation)
Mg(NO3)2 is an oxidizing agent, Mg(NO3)2 is a reducing agent.
Reactant
Search by reactants (Mg(NO3)2)
12345
1 Mg(NO3)2 → O2 + NO2 + MgO2 H2SO4 + Mg(NO3)2 → HNO3 + MgSO43 Mg(NO3)2 + K3PO4 → KNO3 + Mg3(PO4)24 Na2SO4 + Mg(NO3)2 → NaNO3 + MgSO45 HCl + Mg(NO3)2 → HNO3 + MgCl26 NaOH + Mg(NO3)2 → NaNO3 + Mg(OH)27 KOH + Mg(NO3)2 → KNO3 + Mg(OH)28 Cu + Mg(NO3)2 → Mg + Cu(NO3)29 KI + Mg(NO3)2 → KNO3 + MgI210 Mg(NO3)2 → O2 + Mg(NO2)212345Search by products (MgO, NO2, O2)1 Mg(NO3)2 → O2 + NO2 + MgOSearch by reactants (Mg(NO3)2) and by products (MgO, NO2, O2)1 Mg(NO3)2 → O2 + NO2 + MgOExplanation:
i hope that helps❤4. NaOCI3 oxidation number
Answer:
NaHCO3 is +4. Sodium has a +1 oxidation state. Hydrogen has a +1 oxidation state.
5. oxidation number of S
Answer:
-2
Explanation:
The sulphur has an oxidation state of -2. Oxidation state shows the total number of electrons which have been removed from an element (a positive oxidation state) or added to an element (a negative oxidation state) to get to its present state.
Answer:
The answer is -2
Explanation:
#CarryOnLearning
6. oxidation number of calcium
Answer:
+1
Explanation:
the oxidation number of an atom is the charge that atom would have if the compound was composed of ions. 1. ... The oxidation number of simple ions is equal to the charge on the ion. The oxidation number of sodium in the Na+ ion is +1, for example, and the oxidation number of chlorine in the Cl- ion is -1.
7. oxidation number of iodine
Answer:
iodine
atomic number 53
melting point 113.5 °C (236 °F)
boiling point 184 °C (363 °F)
specific gravity 4.93 at 20 °C (68 °F)
oxidation states −1, +1, +3, +5, +7
Explanation:
sana makatulong
8. oxidation number of P
Answer:
P4
I don't know if thats correct just my opinion
9. what is the number of moles in 432g Ba(NO3)2?
Answer:
261.344
Explanation:
Answer:
⇒ 1.65 moles
Explanation:
The molecular weight is: Ba=137.33, N = 14.007 x 2, O = 16.00 x 6. Added together, it is 261.344. 432/261.344 = 1.653. Since the answer should have 3 significant figures, the answer should be 1.65 moles.
#UlloriaqEmpire
10. an..! ACTIVITY #2 (Show your solution) 1. Find the oxidation number of N in HNO3. 2. What is the oxidation number of S in H₂SO4. 3. Find the oxidation number of B in BO3-3.
Answer: 1. Being a neutral compound,the sum of oxidation numbers of all atoms present in nitric acid is zero. Hence, the Oxidation Number of Nitrogen in HNO3 H N O 3 is +5.
yan lang alam q AHAHA
11. What is the oxidation number of phosphorus in each of the following oxides?
Answer:
i hope it help
Explanation:
Explanation:
You're dealing with an ion, the phosphate anion to be precise, which means that the oxidation states of each atom must add up to give the overall charge of the ion.
So, start by writing down what you know. You know that
the ion has a (3-) overall charge
the ion is made up of one phosphous atom and four oxygen atoms
oxygen's oxidation state in most compounds is −2.
This means that you can write
one phosphorus atom1×ONP+4×ONoxygenfour oxygen atoms=−3
Solve the equation for ONP to get
ONP+4×(−2)=−3
ONP=−3+8=+5
So, phosphorus has a +5 oxidation state in the phosphate anion, PO3−4.
12. what number of moles of Pb(NO3) is consumed when 54g of KNO3 is produced?
Answer:
Pb(NO3)2 + 2KCl = 2KNO3+PbCl2.54 x 325 / 202 = 86.8813. sulfur oxidation number?
Answer:
Sulphur exhibits oxidation numbers of -2, 0, +2, +4 and +6. Oxidation number -2 is seen in the sulphide ion, S--, and a typical compound is H2S, hydrogen sulphide or hydrosulphuric acid.14. reactant losses or gains electrons, undergone oxidation or reduction reaction, and is a reducing agent or an oxidizing agent. Show process. 1. Cu→ 2. AgNO3→ 3. Mg → 4. SiCl4 → 5. Zn2+ → Cu (NO3)2
Answer:
huhhivvuuggibbiivvvvvgg
15. ormula, and Molecular Formula A. Calculate the percentage composition of the following compounds and molecules: 1. Caffeine, CH₁N40₂2 '10' 2. Ammonium nitrate, NH NO3 3. Benzene, CH₂ 4. Iron(II) oxide, FeO 5. Iron(III) oxide, Fe₂O3
1. Caffeine, C8H10N4O2
To calculate the percentage composition of caffeine, we need to find the molar mass of the molecule first:
Molar mass of Caffeine = (8 x 12.01 g/mol) + (10 x 1.01 g/mol) + (4 x 14.01 g/mol) + (2 x 16.00 g/mol) = 194.19 g/mol
Now we can find the percentage composition of each element in caffeine:
Percentage of Carbon = (8 x 12.01 g/mol) / 194.19 g/mol x 100% = 49.48%
Percentage of Hydrogen = (10 x 1.01 g/mol) / 194.19 g/mol x 100% = 5.19%
Percentage of Nitrogen = (4 x 14.01 g/mol) / 194.19 g/mol x 100% = 28.85%
Percentage of Oxygen = (2 x 16.00 g/mol) / 194.19 g/mol x 100% = 16.48%
2. Ammonium nitrate, NH4NO3
To calculate the percentage composition of ammonium nitrate, we need to find the molar mass of the molecule first:
Molar mass of Ammonium Nitrate = (1 x 14.01 g/mol) + (4 x 1.01 g/mol) + (3 x 16.00 g/mol) = 80.04 g/mol
Now we can find the percentage composition of each element in ammonium nitrate:
Percentage of Nitrogen = (1 x 14.01 g/mol) / 80.04 g/mol x 100% = 17.50%
Percentage of Hydrogen = (4 x 1.01 g/mol) / 80.04 g/mol x 100% = 5.03%
Percentage of Oxygen = (3 x 16.00 g/mol) / 80.04 g/mol x 100% = 37.51%
Percentage of Ammonium ion (NH4+) = (4 x 1.01 g/mol + 1 x 14.01 g/mol) / 80.04 g/mol x 100% = 40.96%
3. Benzene, C6H6
To calculate the percentage composition of benzene, we need to find the molar mass of the molecule first:
Molar mass of Benzene = (6 x 12.01 g/mol) + (6 x 1.01 g/mol) = 78.11 g/mol
Now we can find the percentage composition of each element in benzene:
Percentage of Carbon = (6 x 12.01 g/mol) / 78.11 g/mol x 100% = 92.26%
Percentage of Hydrogen = (6 x 1.01 g/mol) / 78.11 g/mol x 100% = 7.74%
4. Iron(II) oxide, FeO
To calculate the percentage composition of iron(II) oxide, we need to find the molar mass of the molecule first:
Molar mass of Iron(II) oxide = 55.85 g/mol + 16.00 g/mol = 71.85 g/mol
Now we can find the percentage composition of each element in iron(II) oxide:
Percentage of Iron = 55.85 g/mol / 71.85 g/mol x 100% = 77.67%
Percentage of Oxygen = 16.00 g/mol / 71.85 g/mol x 100% = 22.33%
16. copper (ll), oxide, CuD is a black solid often used as a pigment in ceramics. it is used to produce blue, green, and red glazes. there are several ways of producing CuD, one of which is heating copper (ll) nitrate,Cu(NO3)2 as shown in the equation:2Cu(NO3)2 -> 2 CuO + 4 NO2+ O2Determine the number of moles of Cu(NO3)2 needed to produce 6.75 moles of nitrogen dioxide, NO2. with solutions
Solve you own paper cause it you test will be fail lol
17. oxidation number of lithium?
Answer:
lithium's oxidation number is 1
Answer:
It's one(1)
Sana maka help ❤️
18. oxidation number of calcium
The oxidation number of calcium is +1
19. Why does oxidation number of phosphorus oxides vary?
Answer:
[tex]\huge\bold\red{{Ghost Squad}}[/tex]
[tex]\green{ \rule{10pt}{3000pt}}[/tex]
20. Oxidation number of Br?
Answer:
-1
Explanation:
Answer:
-1
Explanation:
Br has a -1 oxidation number, except when bonded to a F, a Cl, or an O.
21. oxidation number for SO32-
Answer:
Sulfur (+6) & Oxygen (-2), because SO3(g) has no charge
(SO₃)^(2-)So
The oxidation charge for S is 6+
While the Oxidation charge for O is 2-
22. The oxidation number of a species increases when it undergoes oxidation.
Answer:
true
Explanation:
A loss of negatively-charged electrons corresponds to an increase in oxidation number, while a gain of electrons corresponds to a decrease in oxidation number. Therefore, the element or ion that is oxidized undergoes an increase in oxidation number.
Answer:
Ty for the points
23. 6. An oxidation-half reaction always involves the ____. a. Gain in electrons and a decrease in oxidation number b. Gain in electrons and an increase in oxidation number c. Loss in electrons and a decrease in oxidation number d. Loss in electrons and an increase in oxidation number
Answer:
A
Explanation:
SANA MAKATULONG PA BRAINLIEST NALANG PO ;)
24. calculate the number of moles of oxygen atoms in 2.52 g Ca(NO3) 2
Solution:
Step 1: Calculate the molar mass of Ca(NO₃)₂.
molar mass = (40.08 g × 1) + (14.01 g × 2) + (16.00 g × 6)
molar mass = 164.10 g
Step 2: Calculate the number of moles of O.
[tex]\text{moles of O = 2.52 g Ca(NO₃)₂} × \frac{\text{1 mol Ca(NO₃)₂}}{\text{164.10 g Ca(NO₃)₂}} × \frac{\text{6 mol O}}{\text{1 mol Ca(NO₃)₂}}[/tex]
[tex]\boxed{\text{moles of O = 0.0921 mol}}[/tex]
#CarryOnLearning
25. oxidation number of Se
Answer:
+4
Se = Se
Explanation:
34. 78.96
Se
[Ar] 3d104s24p4
26. what is the oxidation number of NO2
Answer:
+4
Explanation:
Oxidation states of nitrogen
Ox. state Species
+5 NO3
- Nitrate ion, oxidizing agent in acidic solution.
+4 NO2 Nitrogen dioxide, a brown gas usually produced by the reaction of concentrated
nitric acid with many metals. It dimerizes to form N2O4.
+3 NO2
- Nitrite ion in basic solution and nitrous acid in acidic solution. Can be either an
oxidizing agent to usually produce NO(g) or a reducing agent to form the nitrate
ion.
+2 NO Nitrogen oxide also called nitric oxide. A colorless gas produced by the reaction
of metals with dilute nitric acid which then reacts with O2 in the air to form the
brown NO2 gas.
+1 N2O Dinitrogen oxide also called nitrous oxide or laughing gas.
0 N2 Commonly found in air and vry unreactive because of the very strong triple bond.
-1 NH2OH Hydroxylamine, a weak base, which can act as either an oxidizing agent or
reducing agent.
-2 N2H4 Hydrazine, a colorless liquid, is a weak bse. Used as a rocket fuel. It
disproportionates to N2 and NH3.
-3 NH3 In basic solution and as NH4
+ in acidic solution. Not genrally used as a reducing
agent in aqueous solutions. When ammonia is burned in the presence of oxygen it
is oxidized to either N2 or NO. The oxidation of ammonium salts usually
produces nitrogen gas.
27. oxidation number of N
Answer:
+3
Explanation:
is the oxidation of n
28. what is oxidation number
Answer:
Oxidation number, also called oxidation state, the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.
Explanation:
Answer: wag laging umasa kay Brainly sis,
Explanation:
Kaya mo yan Laban lang alaxan
29. Calculate the number of ions in 0.853 mole of NO3-.
Answer:
0o.8533 is answer
Explanation:
yan baby
30. oxidation number of calcium
Answer:
+1
Explanation:
I hope it's help, stay safe
Answer:
+1
Explanation:
The oxidation number of calcium is=+1
Hope it helps
Stay safe
Godbless you
