13. A girl is 162 millimeters long. How long is it in meters?a. 0.162 mb. 1.62 mC. 16.2 md. 162 m14. If the length of a stick is 0.624 meter, how long is it in centimeters?a. 0.624 cmb. 6.24 cmc. 62.4 cmd. 624 cm15. Jose walks 378 meters, while Rene walks 0.67 kilometer. What is the differencebetween the distances they walked in centimeters?a. 29, 200 cm b. 2,920 cmc. 292 cm d.292,000 cm
1. 13. A girl is 162 millimeters long. How long is it in meters?a. 0.162 mb. 1.62 mC. 16.2 md. 162 m14. If the length of a stick is 0.624 meter, how long is it in centimeters?a. 0.624 cmb. 6.24 cmc. 62.4 cmd. 624 cm15. Jose walks 378 meters, while Rene walks 0.67 kilometer. What is the differencebetween the distances they walked in centimeters?a. 29, 200 cm b. 2,920 cmc. 292 cm d.292,000 cm
Answer:
13. A girl is 162 millimeters long. How long is it in meters?
a. 0.162 m
14. If the length of a stick is 0.624 meter, how long is it in centimeters?
c. 62.4 cm
15. Jose walks 378 meters, while Rene walks 0.67 kilometer. What is the difference between the distances they walked in centimeters?
d.292,000 cm (I actually think the answer is none of the options. The difference between them is 6 322m, when converted into cm is 632 200cm)
Step-by-step explanation:13. To convert mm to m, divide it by 1000.
14. To convert m to cm, multiply it with 100.
15. First, convert km to m (multiply by 1000). Subtract to see the difference (6 700-378=6 322). Then, convert into cm (multiply by 100).
2. Pqgpipiliiana. 261 cm²b.216 cm²c.162 cm²d. 126 cm²
Answer:
b po ang answer jan
Step-by-step explanation:
i hope nakatulong
3. a box is 162 cm long 12 cm wide and 5.3 cm high find its volume.
Answer: 10,303.2 cm^3
Explanation:
Volume=lxwxh
=162×12×5.2
4. ePOST TESTDirections: Find the area of the given composite figures.A. 160 cmC. 164 cmD. 166 cm12 cmB. 162 cm22 m2.14 m2C. 18 m2D. 20 m2В.16 m2Zm3.A.S6.11 cm86.12 cmC. 86.13 cmD. 86.14 cmB.6cmD12 cm6 cm4. 5 cmA.25 cm?30 cmC. 40 cmD. 50 cm2В.14 cm5.A. 13.42 ft2B. 12.42 ft2C. 11.42 ft2D. 10.42 ft22 feet
Answer:
1.a.
2.a.
3.c.
4.b.
5.a.
Step-by-step explanation:
give me an thanks and brainliest
5. Elena and Claris are comparing their height.If Elena height is 162 1/3 cm and Claris height is 150 1/4 cm,what is the difference in their heights?
Answer:
12 1/12
Step-by-step explanation:
TYSMMM! (pa brainliest Salamat)
6. Maria’s front yard is shaped like a parallelogram. It has a dimension of 9 cm and 18 cm. What is the area of the front yard? A.162 square cm B. 172 square cm C. 182 square cm D. 192 square cm
Answer:
A.162 square
Step-by-step explanation:
sinulat ko po yan sa papel para mag sagot nyan
7. The length of Mathatics Garden is twice its width. If the area is 162 sq. m., find the dimensions of the garden
Answer:
Given:
x = width2x = lengthArea = 162 sq. m.Solution:
Width × Length = Area
x × 2x = 162 sq. m.
2x² = 162 sq. m.
2x²/2 = 162 sq. m./2 (divided by two)
x² = 81
√x² = √81 (square root)
x = 9
Therefore,
x = 9m The width is 9m
2x = 2(9) = 18m The length is 18m.
8. what is the standard division of 160 cm 166 cm 155 cm 158 cm 162 cm 170 cm 156 cm 153 cm
Answer:
5.78 cm
Step-by-step explanation:Formula:
[tex]\sf \sigma = \sqrt{\frac{\sum(x_i - \mu)^2}{n-1} }[/tex]
[tex]\textsf{where} \begin{cases} \sf n = number \: of \: terms\\\sf \mu = mean\\\sf x_i = individual \: values \: of \: the \: terms \: on \: the \: sample\end{cases}[/tex]
Solution:
[tex]\sf \textsf{Given: } \{160,166,155,158,162,170,156,153\}[/tex]
[tex]\sf In \: this \: case, \; x_i = \{160,166,155,158,162,170,156,153\}[/tex]
[tex]\sf By \: counting \: the \: number \: of \: terms, \: n = 8[/tex]
[tex]\textsf{Solving for the mean }\sf \mu,[/tex]
[tex]\sf \mu = \frac{160+166+155+158+162+170+156+153}{8} = 160[/tex]
[tex]\therefore \sf (x_i - \mu)^2 = \begin{cases} \sf (160 - 160)^2 = 0\\ \sf (166 - 160)^2 = 36 \\ \sf (155 - 160)^2 = 25 \\ \sf (158 - 160)^2 = 4 \\ \sf (162 - 160)^2 = 4 \\ \sf (170 - 160)^2 = 100 \\ \sf (156 - 160)^2 = 16 \\ \sf (153 - 160)^2 = 49\end{cases}[/tex]
[tex]\sf It \: follows \: that[/tex]
[tex]\sf \sum(x_i-\mu)^2 = 0 + 36 + 25 + 4 + 4 + 100 + 16 + 49\\\text{} \quad \quad \quad \quad \ \ \ = 234[/tex]
[tex]\sf Substituting \: to \: the \: formula,[/tex]
[tex]\sf \sigma = \sqrt{\frac{\sum(x_i - \mu)^2}{n-1} } = \sqrt{\frac{234}{8-1} }[/tex]
[tex]\sf \sigma = \sqrt{33.4285714286} \approx 5.78 \: cm[/tex]
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9. 10. A box is 162 millimeters long. How long is it in meters?A. 16.2 mB. 1.62 mC.0.162 mD. 0.0162 m
Answer:
A.Step-by-step explanation:
I HOPE IT HELPS YOU#STAY SAFE#CARRYONLEARNINGPA BRAINLIEST NADIN[tex] \red{ \boxed{0.162}}[/tex]A box is 162 millimeters long. How long is it in meters?
A. 16.2 m
B. 1.62 m
C.0.162 m
D. 0.0162 m
Why?1 millimeter=.001 meters
Since there are 162 millimeters, we need to multiply 162 and .001
[tex] \tt162 \times .001 = .162[/tex]162x.001 is equal to .162
So, there are .162 meters in 162 millimeters.
#CarryOnLearning10. The heights (in cm) of 11 players of a team are as follows: 160, 158, 158, 159, 160, 160, 162, 165, 166, 167, 170.
Answer:
hope it helps
Step-by-step explanation:
The given heights of the 11 players are:
160, 158, 158, 159, 160, 160, 162, 165, 166, 167, 170.
To calculate some basic statistics for this data set, we can use the following formulas:
1. Mean (Average) Height:
The mean or average height can be calculated by adding all the heights and dividing the sum by the total number of heights:
Mean height = (160+158+158+159+160+160+162+165+166+167+170) / 11
= 166 / 11
= 15.09
So, the mean or average height of the players is approximately 159.09 cm.
2. Median Height:
To find the median height, we need to arrange the heights in ascending or descending order and then find the middle value. Since we have an odd number of values, the median is the middle value when the heights are arranged in order:
158, 158, 159, 160, 160, 160, 162, 165, 166, 167, 170.
So, the median height is 160 cm.
3. Mode Height:
The mode height is the most frequent value in the data set. In this case, the heights 160 cm is the most frequent since it occurs three times. Therefore, the mode height is 160 cm.
Range of Heights:
The range of heights is the difference between the highest and lowest value in the data set. In this case, the highest height is 170 cm and the lowest is 158 cm. Therefore, the range of heights is:
Range = highest height - lowest height
= 170 - 158
= 12 cm
So, the range of heights is 12 cm.
11. The mean height of a class of 28 students is 162 cm. A new student with a height of 156 cm joins the class. what is the mean height of the class now?
Answer:
Total height of students in the class (before) = 28×162 cm
= 4536 cm
Total height of students in the class (now) = 4526 + 156
= 4692 cm
Mean height (now) ([tex]\frac{Total height}{Total number of students}[/tex]) = [tex]\frac{4692}{28+1}[/tex] = 161 [tex]\frac{23}{29}[/tex] cm
12. a box is 162 cm long 12 cm wide and 5.3 cm high find its volume.
162*12*5.3
1944*5.3
V= 10303.2
13. ∠ABC and ∠XYZ are complementary angles. If m∠XYZ = 28, what is m∠ABC? A. 162 B. 172 C. 62 D. 72
Answer:
62
Step-by-step explanation:
Angles that are complementary has a sum of 90 degrees. Thus, the other angle must be.
90-28=62 degrees
14. m when 8 162 is added to the difference of 63785 and 25 94?0.38.563
Answer:
nakakalito po ,, pwede ayusin mo yung tanong mo ?
15. Find the area of the whole frame in Number 9 if x = 2 cmA. 81 cmB. 162 cm2 C. 225 cm?D. 324 cm
Answer:
A.81cm
Step-by-step explanation:
9×x(2)=81
9×9=81
16. Paolo interviewed 50 out of 230 students and noted that their average height is 162 cm. What is the statistical term for Paolo's description of the group
Answer:
The statistic term of that is STATISTICAL
Step-by-step explanation:
HOPE IT HELPS <8
17. 5. What is the final answer?a. 162 cmb. 126 cmc. 216 cmd. 369 cm
What is the final answer?
a. 162 cm
b. 126 cm
c. 216 cm
d. 369 cm
B. 126 cm18. x² = 162[tex]x2 = 162[/tex]x² =162
and I have a great day to be a great day to be a great day to be a
100,827,927
is the multiple the time and divide the morning
19. Find the perimeter of the figure below 18 cm. 9 cm. a.27 cm b.54 cm c.81 cm d.162 cm
Answer:
B
Step-by-step explanation:
54 cm kasi i add mo lng lahat pa follow na den
20. A 125 m3 162 mC216 mD512what is the appropriate unit of measure in finding the volume ofrectangular poolComWhich ustrationof the figures 72 m
Question:
what is the appropriate unit of measure in finding the volume of
rectangular pool?
Answer:
MetersStep-by-step explanation:
I hope it helps!Correct me if im wrong!:)
21. a box is 162 cm long 12 cm wide and 5.3 cm high find its volume.
the total is 9,803.2 cm.^3
22. The area of a rectangular field is 162 sq m and its length is twice its width. what is the equation
Answer:
Give me the pic
Explanation:
Thx in points
23. The length of Mathematics Garden is twice its width. If the area is 162 sq. m., find thedimensions of the garden.
Answer:
The dimensions are 18m by 9m
Step-by-step explanation:
Find two numbers that will match the rule
24. 3. What is the area of the rectangle?a. 172 cmd. 162 cmb. 182 cmc. 192 cm
Answer:
A. 172 cm
Step-by-step explanation:
hope it helps
correct me if im wrong
#CarryOnLearning
25. a box is 162 cm long 12 cm wide and 5.3 cm high find its volume.
10,303.2 cubic centimeters
26. Simmi is 162 cm tall. If she jumps 48 cm off the ground, howhigh does the top of her head reach from the ground?
Simmi is 162 cm tall. If she jumps 48 cm off the ground, how
If she jumps 48 cm off the ground, howhigh does the top of her head reach from the ground?
simmi's height =
[tex]152cm[/tex]
she jumps
[tex]48 \: cm \: to \: ground \: [/tex]
[tex]152 \: cm \: + 48cm \: = 200cm \: [/tex]
27. if mSYU=162°and mST=38°,what is the m<SRU?
Answer:
62°
Step-by-step explanation:
SRU = 1/2 (162°-38°)
SRU = 1/2 (124°)
SRU = 62°
28. the diagonal of a square has a length of 18cm. find the area of the squarea. 126 cm²b. 162 cm²c. 16.2 cm²d. 12.6 cm²
ANSWER:B. 162 cm²SOLUTION:[tex] \frac{18 \times 18}{2} = 162 {cm}^{2} [/tex]
29. 14. Fredirick and Delson are comparing their heights. If Fredirick'sheight is 158 cm and Delson's height is 162 cm. What is thedifference in their heights?
Answer:
The difference in their height is that Fredirick's is 4 cm taller than Delson
Answer:
Delson is taller than Frederick which is Delson's height is 162 cm, while Frederick's height is 158 cm. The difference of their height is 4 cm.
Step-by-step explanation:
162 - 158 = 4Hence, tge difference between their height is 4 cm.30. 10. A pyramid has a base area of 24 cm and a height of 6 cm. What is the volume of the pyramid? A. 24 cm B. 48 cm C. 144 cm D. 162 cm
Answer:
Problem:10. A pyramid has a base area of 24 cm and a height of 6 cm. What is the volume of the pyramid?
Solution:Formula: ⅓bh[tex]\\[/tex] [tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex]⅓ (24 cm)(6 cm)
[tex]\\[/tex] [tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex]⅓(144 cm)
[tex]\\[/tex] [tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex] [tex]{\boxed{\tt\red{V\:=\:47.9952\:cm³\:≈\:48\:cm³}}}[/tex]
====================================
[tex]\tt{{Nam\:Shin}}[/tex] ❤️
#CarryOnLearning
Answer:
Problem:10. A pyramid has a base area of 24 cm and a height of 6 cm. What is the volume of the pyramid?
Solution:[tex]\sf{{Formula: \:⅓bh}}[/tex]
[tex]\\[/tex] [tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\sf{{⅓\: (\:24\: cm\:)(\:6 \:cm\:)}}[/tex]
[tex]\\[/tex] [tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\sf{{⅓\:(\:144 \:cm\:)}}[/tex]
[tex]\\[/tex] [tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex][tex]\\[/tex] [tex]\sf{{V\:=\:47.9952\:cm³\:≈\:48\:cm³}}[/tex]
Therefore, the volume of a pyramid is 48 cm³.
====================================
[tex]\sf{{If\:you\: have\:any\: questions\:feel\:free\:to\:ask\:me.}}[/tex] [tex]\sf{{Have\:a\:nice\:and\:great\:day!}}[/tex]
[tex]\sf{{MishSelenia⚘}}[/tex]
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