Replace the loading system by an equivalent resultant force and specify where the resultant’s line of action intersects the beam measured from O, in ft. Given P=445 lb, L=7 ft.​

1. Replace the loading system by an equivalent resultant force and specify where the resultant’s line of action intersects the beam measured from O, in ft. Given P=445 lb, L=7 ft.​

sorry di kita matutulunganStep-by-step explanation:

[tex]\mathbb{SOLUTION:}[/tex]

Let:

x = location of the resultant force from point O.

[tex]\\[/tex]

[tex]\mathsf{R={\Sigma}F}[/tex]

[tex]\mathsf{R=6P}[/tex]

[tex]\mathsf{R=6(445)}[/tex]

[tex]\mathsf{R=2670 \: \: lb}[/tex]

[tex]\\[/tex]

[tex]\mathsf{Rx={\Sigma}Fd}[/tex]

[tex]\mathsf{2670x=890(7)+445(14)+1335(21)}[/tex]

[tex]\mathsf{2670x=40495}[/tex]

[tex]\mathsf{x=\dfrac{40495}{2670}}[/tex]

[tex]\mathsf{x=15.16667}[/tex]

[tex]\\[/tex]

[tex]\mathbb{ANSWER:}[/tex]

Resultant force: [tex]\boxed{\textsf{R = 2670 lb}}[/tex]

Location of the resultant force from point O: [tex]\boxed{\textsf{x = 15.16667 ft}}[/tex]